Chem

#7
by puffy310 - opened

๐Ÿ˜ƒ:

Write about Phosphorus, Francium, Bromine, Gallium, Magnesium, Selenium in the following format.
Group #: (Horizontal Group on the periodic table)
# val.e = (Amount of valence electrons)
Ion Steps:
1. (Is there more or less then 4 valance electrons?)
2. (If there are more, put gained, if there are less, put less)
3. (If there is more the charge is 8 minus amount of valance electrons as a negative, if there are less, the charge is 8 minus the a mount of valance electrons as a positive)
4. (Put the element symbol and the answer from 3.)


๐Ÿค–:

Phosphorus:
Group #: 15
# val.e = 5
Ion Steps:
1. There are more than 4 valence electrons.
2. Phosphorus gains 3 electrons to form a P3- ion.
3. The charge is 8 - 5 = -3.
4. The ion is P3-.
Francium:
Group #: 87
# val.e = 1
Ion Steps:
1. There are less than 4 valence electrons.
2. Francium gains 1 electron to form a Fr- ion.
3. The charge is 8 - 1 = +7.
4. The ion is Fr7+.
Bromine:
Group #: 17
# val.e = 7
Ion Steps:
1. There are more than 4 valence electrons.
2. Bromine gains 1 electron to form a Br- ion.
3. The charge is 8 - 7 = -1.
4. The ion is Br-.
Gallium:
Group #: 13
# val.e = 3
Ion Steps:
1. There are less than 4 valence electrons.
2. Gallium gains 3 electrons to form a Ga3+ ion.
3. The charge is 8 - 3 = +5.
4. The ion is Ga3+.
Magnesium:
Group #: 2
# val.e = 2
Ion Steps:
1. There are less than 4 valence electrons.
2. Magnesium loses 2 electrons to form a Mg2+ ion.
3. The charge is 8 - 2 = +2.
4. The ion is Mg2+.
Selenium:
Group #: 16
# val.e = 6
Ion Steps:
1. There are more than 4 valence electrons.
2. Selenium gains 2 electrons to form a Se2- ion.
3. The charge is 8 - 6 = -2.
4. The ion is Se2-.


๐Ÿ˜ƒ:

Now do Chlorine, Boron, Rubidium, and Oxygen.


๐Ÿค–:

Chlorine:
Group #: 17
# val.e = 7
Ion Steps:
1. There are more than 4 valence electrons.
2. Chlorine gains 1 electron to form a Cl- ion.
3. The charge is 8 - 7 = -1.
4. The ion is Cl-.
Boron:
Group #: 13
# val.e = 3
Ion Steps:
1. There are less than 4 valence electrons.
2. Boron gains 3 electrons to form a B3- ion.
3. The charge is 8 - 3 = +5.
4. The ion is B3+.
Rubidium:
Group #: 1
# val.e = 1
Ion Steps:
1. There are less than 4 valence electrons.
2. Rubidium loses 1 electron to form a Rb+ ion.
3. The charge is 8 - 1 = +7.
4. The ion is Rb+.
Oxygen:
Group #: 16
# val.e = 6
Ion Steps:
1. There are more than 4 valence electrons.
2. Oxygen gains 2 electrons to form an O2- ion.
3. The charge is 8 - 6 = -2.
4. The ion is O2-.


๐Ÿ˜ƒ:

Add barium and bismuth


๐Ÿค–:

Barium:
Group #: 2
# val.e = 2
Ion Steps:
1. There are less than 4 valence electrons.
2. Barium loses 2 electrons to form a Ba2+ ion.
3. The charge is 8 - 2 = +2.
4. The ion is Ba2+.
Bismuth:
Group #: 15
# val.e = 5
Ion Steps:
1. There are more than 4 valence electrons.
2. Bismuth gains 3 electrons to form a Bi3- ion.
3. The charge is 8 - 5 = -3.
4. The ion is Bi3-.

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